Commit deb649f0 by Olivier

### Chapter 4: two typo fixes

With thanks to the student who kindly reported them in the last
exercise session.
parent a2f7f266
 \renewcommand{\lastedityear}{2019} \renewcommand{\lasteditmonth}{05} \renewcommand{\lasteditday}{01} \renewcommand{\lasteditday}{10} \renewcommand{\numberofthischapter}{4} \renewcommand{\titleofthischapter}{\namechapterfour} ... ... @@ -25,7 +25,7 @@ %%%% \subsection{Magnitude of the pressure force} \youtubethumb{ke4Rf9FrHnw}{when pressure-induced forces in static fluids matter: 24 hours of heavy tonnage transit through the \textit{Miraflores} locks in Panama. Can you quantify the force applying on a single lock door?}{Y:XyliboxFrance (\styl)} What is the force which which a fluid pushes against a wall? What is the force with which a fluid pushes against a wall? When the pressure $p$ exerted is uniform and the wall is flat, the resulting force $F$ is easily calculated: \begin{IEEEeqnarray}{rCcCl} ... ... @@ -111,7 +111,7 @@ \subsection{The direction of pressure} An important concept is that in continuum mechanics, the flat surface is imaginary. More precisely, a fluid is able to exert pressure on not only on solid surfaces, but also upon and within itself. In this context, we need to rework eq.~\ref{eq_first_def_pressure_two} so that now pressure is defined as perpendicular force per area on an \emph{infinitesimally small} surface of fluid: An important concept is that in continuum mechanics, the flat surface is imaginary. More precisely, a fluid is able to exert pressure not only on solid surfaces, but also upon and within itself. In this context, we need to rework eq.~\ref{eq_first_def_pressure_two} so that now pressure is defined as perpendicular force per area on an \emph{infinitesimally small} surface of fluid: \begin{IEEEeqnarray}{rCl} p &\equiv& \lim_{A \to 0} \frac{F_\perp}{A} \label{eq_def_pressure} \end{IEEEeqnarray} ... ...
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